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Trigonometry 17 Online
OpenStudy (anonymous):

3sin x=2/sinx

OpenStudy (tkhunny):

Have you considered factoring? 1) \(\sin(x) \ne 0\) \(3\sin^{2}(x) - 2 = 0\) \((\sqrt{3}\sin(x) - \sqrt{2})(\sqrt{3}\sin(x) + \sqrt{2}) = 0\) You're almost done!

OpenStudy (kc_kennylau):

Factoring is not necessary

OpenStudy (kc_kennylau):

\[\Large\begin{array}{rcl} 3\sin x&=&\frac2{\sin x}\\ \sin^2x&=&\frac23\\ \sin x&=&\sqrt{\frac23} \end{array}\]

OpenStudy (tkhunny):

No good. You missed the negative solution. I guess factoring was necessary.

OpenStudy (kc_kennylau):

\[\large\begin{array}{rcl} 3\sin x&=&\frac2{\sin x}\\ \sin^2 x&=&\frac23\\ \sin x=\frac23&or&\sin x=-\frac23 \end{array}\]

OpenStudy (tkhunny):

Never much liked the "remember to include the negative" idea. Factoring just hands it to you. No forgetting allowed.

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