Question

help

Answer 1

which question...?

Answer 2

both

Answer 3

ok... for the 1st find the volume of the cube

\[V = 5^3\]

the cylinder has a radius 2.5 cm

so

use the formula

\[V = \pi \times r^2 \times h\]

you know the radius and the height is 6

substitute and find the volume...

the composite volume is found by

Composite Volume = Cube Volume + Cylinder Volume

Answer 4

for the 2nd question find the area of the cross sectional end

\[Hemisphere = \frac{1}{2}\times (\pi \times r^2)\]

the radius is 3

next the triangle

\[\triangle = \frac{1}{2} b \times h\]

the triangle has a base of 6 ft and height of 4ft


add the 2 areas together and call it the cross section area

then use

Volume = cross section area x 10

hope it helps

Answer 5

@campbell_st

Answer 6

what help do you need...?

Answer 7

i dnt get it ur way

Answer 8

for the first shape iis v=1 bh
3

Answer 9

for the second shape v=pier2h

Answer 10

well that is the same

\[V = 5^3 = 5 \times 5 \times 5\]

Answer 11

f0r number one

Answer 12

125

Answer 13

ok... now the cylinder

\[V = \pi \times 2.5^2 \times 6\]

Answer 14

it 15