Question

What is the domain of the function.
y=square root of 3x+3
B. y=square root of 7x-12

Answer 1

\[y=\sqrt{3x+3}\]

Answer 2

Hint for real values of the function 3x+3 cannot be negative
so any value of which makes it negative is not in the domain

Answer 3

* any value of x which makes it negative

Answer 4

note that there is no real square root of a negative

Answer 5

so for example x cannot be -2 because that would make 3x + 3 = -3

Answer 6

b. \[y=\sqrt{7x-12}\]

Answer 7

dont get it

Answer 8

@cwrw238

Answer 9

For the first problem, 3x+3 cannot be negative is same as saying \[3x + 3 \ge 0\]. Solve for x.

Answer 10

oh so it would be

Answer 11

\[x \le-1\]

Answer 12

@ranga

Answer 13

and B would be \[x \ge-\frac{ 7 }{ 12}\]