Mathematics
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OpenStudy (anonymous):
Find the unit vector for each of the following in the direction of the given vector; verify that result has a magnitude of 1
a) u=<0,-2>
b)w=-6i
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ganeshie8 (ganeshie8):
find the magnitude of given vector,
and divide
ganeshie8 (ganeshie8):
a) u=<0,-2>
can u find the magnitude of this vector ?
OpenStudy (anonymous):
Don't know how to
ganeshie8 (ganeshie8):
magnitude of \(<x, y>\) is \(\sqrt{x^2 + y^2}\)
OpenStudy (anonymous):
so 2?
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ganeshie8 (ganeshie8):
|dw:1396741770368:dw|
ganeshie8 (ganeshie8):
yes, magnitude of <0, -2> is simply 2
ganeshie8 (ganeshie8):
so, the unit vector is \(\large <\frac{0}{2}, ~\frac{-2}{2}> = <0, ~-1> \)
OpenStudy (anonymous):
ohh.. That was so simple. Now what about b?
ganeshie8 (ganeshie8):
yup !
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ganeshie8 (ganeshie8):
b)w=-6i
ganeshie8 (ganeshie8):
j component is missing, so write it as below :
b)w=-6i + 0j
ganeshie8 (ganeshie8):
find its magnitude and divide
OpenStudy (anonymous):
okay, thank you. You made this beyond simple.
ganeshie8 (ganeshie8):
good to hear :) so wat did u get for b ?
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OpenStudy (anonymous):
wait, would I find the magnitude of that the same way I did for a?
ganeshie8 (ganeshie8):
yup
OpenStudy (anonymous):
(6,0)?
ganeshie8 (ganeshie8):
b)w=-6i + 0j
in vector form it is :
<-6, 0>
OpenStudy (anonymous):
oh -6. I came close
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ganeshie8 (ganeshie8):
:) find the mag
OpenStudy (anonymous):
6?
ganeshie8 (ganeshie8):
correct ! 6 is the magnitude
to get the unit vector, divide the mag
ganeshie8 (ganeshie8):
unit vector = \(\large \frac{-6i}{6} = -i\)
OpenStudy (anonymous):
Thank you! :)
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ganeshie8 (ganeshie8):
np :)