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if the point (2/3 y) is on the unit circle what is y? a. 2/3 b. 1/3 c. sqrt 5/3 d. 4/9
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All points on the unit circle satisfy the property \(x^2+y^2=1\)
Solve \(\Large\left(\dfrac23\right)^2+y^2=1\) to find the answer
idk if its sqrt of 5/3 or 4/9 because y^2 +4/9=1
Continue please your work
so its 4/9
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No it's not
Step by step please?
\[\Large\begin{array}{rcl} \left(\frac23\right)^2+y^2&=&1\\ \frac49+y^2&=&1\\ y^2&=&\frac59\\ y&=&\frac{\sqrt5}3 \end{array}\]
How did you get 4/9 as the answer?
ohhh ok i didnt do the second half
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