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Find the vertices and foci of the hyperbola with equation (x+5)^2/36 - (y+1)^2/64=1
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First find the center: (-5, -1) then find c: c^2 = a^2 + b^2 (a^2 is under the x term, b^2 is under the y term) foci: (-5 + c, -1) and (-5 - c, -1) vertices (-5 + a, -1) and (-5 - a, -1)
Vertices: (-1, 1), (-1, -11); Foci: (-1, -15), (-1, 5)
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