One factor of
12t^2 − 60t + 48 is t − 1.

Find the other factors, then write the polynomial in factored form.

Question

One factor of 
12t^2 − 60t + 48 is t − 1.

 Find the other factors, then write the polynomial in factored form.

anonymous · Answer

@thewonderfuladele, I think I kinda get this one...maybe lol

anonymous · Answer

Ok, so one factor is already there so that means, GCF would be 12, right?

ranga · Answer

Factor out 12 first.
Then use the AC method to factor.

anonymous · Answer

ok, hold on.

anonymous · Answer

wait, t, not x

ranga · Answer

12t^2 − 60t + 48 = 12(t^2 - 5t + 4) = 12(t -1)(t   ? )

anonymous · Answer

12(t-1)(t+4)?

ranga · Answer

t - 4

anonymous · Answer

omg, I was gonna say -4, but I always get positives & negatives mixed up

ranga · Answer

You can also solve this by synthetic division:
Divide    12  - 60   + 48    by  +1  (since t-1 is a factor)

ranga · Answer

1  |  12  - 60   + 48
    |        +12   - 48
    |__________________________
       12  -48         0

So (12t - 48) is the other factor.
Factor out 12:
12(t - 4)

So the factored form is: 12(t-4)(t-1)