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Trigonometry 12 Online
OpenStudy (anonymous):

sin(pi/4-x)=0

OpenStudy (anonymous):

pi/4=45 sin(45-x)=0 we know that sin(360) equals zero...

OpenStudy (johnweldon1993):

^ also sin(0) = 0

OpenStudy (anonymous):

yeah, that too:)

OpenStudy (anonymous):

Would it be correct to solve it this way? \[\pi/4-x=\pi*k\] \[-x=\pi*k-\pi/4\] \[x=-\pi*k+\pi/4\]

OpenStudy (anonymous):

I don't think it makes any sense. but this is just me, and I really need to finish my English work, sorry and bye.

OpenStudy (johnweldon1993):

I see no reason to solve it like that Especially because you will then have 2 unknowns...easier to just remember pi/4 =180/4 = 45

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