Simplify the rational expression state any excluded values. A. 2 x-8/x-4 B. 4x-8/4x+20
\[\frac{ 2x-8 }{ x-4 }\]
b. \[\frac{ 4x-8 }{ 4x+20 }\]
Hey @EmeraldSunset do you know how to do these?
@dumbcow @phi i really need help!
in 2x -8 what number can you divide into each term ?
by 2
so you end up with\[x-4\]
yes, you can divide 2x-8 by 2 you can write it as 2(x-4) (notice that if you "distribute" the 2, you get 2x-8, which is what you started with) now use the idea that anything divided by itself is 1 (except zero divided by zero) \[ \frac{2(x-4)}{x-4} = 2 \cdot \frac{x-4}{x-4}= 2\cdot 1 = 2\] there is one complication: 0/0 is not defined. If x=4 we would have 4-4/(4-4)= 0/0 and that is not allowed. To handle that, we say the answer is 2, with the restriction x≠ 4
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