Ask your own question, for FREE!
Geometry 13 Online
OpenStudy (anonymous):

1. A prism has total surface area of 360 m2 and volume of 60 m3. a.) What are possible lengths of the figure? i. Length: ii. Width iii. Height

OpenStudy (mathstudent55):

Is there a figure?

OpenStudy (anonymous):

no it just gives measurements

OpenStudy (mathstudent55):

What are the measurements? If you need help with a question, you need to supply all the information you were given.

OpenStudy (anonymous):

It is, surface area of 360 cm^2 and volume of 60 cm^2.

OpenStudy (mathstudent55):

Ok. Are you given choices for the answer?

OpenStudy (anonymous):

No it wants me to give the answers

OpenStudy (mathstudent55):

Ok. Do you know what a prism looks like, and how to calculate its surface area and volume?

OpenStudy (anonymous):

rectangular prism

OpenStudy (mathstudent55):

Here's a rectangular prism. |dw:1396909906469:dw|

OpenStudy (anonymous):

Is volume 60 cm^3 = 4L*3W*5H? Would that be the answer?

OpenStudy (mathstudent55):

The volume of a rectangular prism is: \(V = LWH\)

OpenStudy (mathstudent55):

L = 4 m W = 3 m H = 5 m Does work, because \(V = LWH = (4 m)(3 m)(5 m) = 60 m^3\) Now you have to see if these three dimensions also work for the surface area.

OpenStudy (mathstudent55):

The total surface area of a rectangular prism is: \(A = 2(LW + LH + WH) \)

OpenStudy (mathstudent55):

Now you need to see if those numbers also work to give you \(360 ~m^2\) of surface area.

OpenStudy (mathstudent55):

\(A = 2(LW + LH + WH)\) \(A = 2[(4 ~m)(3 ~m) + (4 ~m)(5 ~m) + (3 ~m)(5 ~m)] \) \(A = 2(12 ~m^2 + 20 ~m^2 + 15 ~m^2) \) \(A = 2(47 ~m^2) \) \(A = 94 ~m^2 \) As you can see, the area is too small. You need different dimensions.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!