Question

geometry help!

Answer 1

\(\bf cos(\theta)=\cfrac{\textit{adjacent side}}{hypotenuse}\implies \cfrac{a=-4}{c=5}\)

so we're in the 2nd Quadrant, with a hypotenuse of 5 and a "a value" of -4 so

so use the pythagorean theorem to find "b" \(\bf c^2=a^2+b^2\implies \sqrt{c^2-a^2}={\color{blue}{ b}}\qquad sin(\theta)=\cfrac{{\color{blue}{ b}}}{c}\)