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Using the Fermi-Dirac equation, calculate the energy range about EF (= 3 eV) between F(E) = 0.9 and F(E) = 0.1 at 1000K. Express your result as EF ± delta E, that is, 3 ± delta E eV
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Consider the equation for a Fermi-Dirac distribution:\[f(E)=\frac{ 1 }{ e ^{\left( E-E _{F} \right)/kT}+1}\]You're given two f(E) values, EF, and T. k is Boltzmann's constant. So you simply need to solve the above equation for E, right?
I should have included your name, @xuebowei, since it's been a while since you posted this.
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