in a triangle two sides that measure 6cm and 10cm form an angle that measures 80 degrees. find, to the nearest degree, the measure of the smallest angle in the triangle.

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anonymous · Answer

@mathslover

anonymous · Answer

@Hero

anonymous · Answer

@thu1935

anonymous · Answer

plz help me!

anonymous · Answer

You can use the law of cosine to find stuff

anonymous · Answer

i did tht but im stuck in the middle and need someone to help me out on tht step

anonymous · Answer

okay I got it. You use the law of cosine to the find the third side. Then you use the law of sines to find the other two angles

anonymous · Answer

So once you have a second side, you can use that and the given angle to find the missing angles.

anonymous · Answer

hmm I just repeated myself

anonymous · Answer

can i tel u what i did and wher i got stuck?

anonymous · Answer

okay

anonymous · Answer

First, Find a by the trig identity: a^2 = b^2 + c^2 - 2bc|dw:1397014553141:dw|*cos A