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what is the parallel to 2x-3y=4 passing through (2,6)
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first i am going to rewrite the equation in the form y=mx+c 2x-3y=4 -3y=4-2x y=-4/3+2/3x \[y=\frac{ 2 }{ 3 }x-\frac{ 4 }{ 3 }\]
from this we can see that the gradient of that equation is m=2/3
If this new line is parallel to this equation then it will have the same gradient.. therefore m=2/3 .. and from the question we have a given coordinate (2,6)
what we can do now is use this information to obtain that new equation y-y1=m(x-x1) y-6 =(2/3)(x-2) expand \[y-6=\frac{ 2 }{ 3 }x-\frac{ 4 }{ 3 }\] then add 6 t bth sides \[y=\frac{ 2 }{ 3 }x-\frac{ 22 }{ 3 }\]
Marigirl, many thanks for your help.
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no prbs! can u plz give me a medal
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