For a closed cylinder with radius r cm and height h cm, find the dimensions giving the minimum surface area, given that the volume is 8 cm3.
Write the EXACT answers.
r=_____
h=_____
please explain? :) thanks!! @Luigi0210
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OpenStudy (anonymous):
I use these right?
V= π * r^2 * h
and
A= π * r * (2h+r)
?
OpenStudy (anonymous):
and do i set it like this?
8=π * r^2 * h
h=8/π * r^2 ?
OpenStudy (agent0smith):
Differentiate the SA equation, set it equal to 0 to find where it's a minimum.
OpenStudy (anonymous):
it's a closed cylinder, not an opened one. Your surface area formula is incorrect
OpenStudy (anonymous):
ahh okay
darn..
so how would we solve this problem then?
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OpenStudy (agent0smith):
Yeah it should be \[\large SA = 2 \pi r h + 2 \pi r^2\]
OpenStudy (anonymous):
A = 2pi r^2 + 2pi r h = 2pi r (r + h)
OpenStudy (anonymous):
ohhh okay
so then you set it equal to 8?
OpenStudy (anonymous):
and V = pi r^2 h
OpenStudy (anonymous):
so is it 8=pi r^2 h
so solving for h, h= 8 / pi r^2 ?
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OpenStudy (anonymous):
yes V = pi r^2 h
OpenStudy (anonymous):
8 = pi r^2 h
OpenStudy (anonymous):
so solving for h right?
h= 8
--------
π r^2 ?
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
and then set A' = 0, and solve for r. Once you have r, you can find h.
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OpenStudy (anonymous):
A' ? the derivative of 2pi r (r + h) ?
OpenStudy (anonymous):
not sure what to do here :/
OpenStudy (anonymous):
@sourwing ? @agent0smith ?
OpenStudy (agent0smith):
Plug that equation for h into the SA formula.
Then differentiate w.r.t. r.
OpenStudy (anonymous):
wrtr?
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OpenStudy (anonymous):
so 2πrh+2πr^2
= 2πr(8/π r^2) + 2 π r^2 ?
OpenStudy (anonymous):
= 16πr + 2π r^2
-----------------
π r^2 ?
OpenStudy (anonymous):
correct. Then find dA/dr
OpenStudy (anonymous):
the derivative?
OpenStudy (anonymous):
how can I do that? i'm not quite sure :(
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OpenStudy (anonymous):
@sourwing ?
OpenStudy (anonymous):
A = 2πr(8/π r^2) + 2 π r^2
A = 16 / r + 2pi r^2
A' = -16/r^2 + 4pi r
OpenStudy (anonymous):
ohhh okay i see
so what do we do from here?
OpenStudy (anonymous):
set it equal to 0 and solve for r
OpenStudy (anonymous):
okay so
-16
---- + 4πr = 0
r^2
-16/r^2 = -4πr
-16 = -4πr * r^2
-16 = -4πr^3
4/π = r^3 ?
did I do that right so far? @sourwing :/
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so r=4/π^(1/3)
OpenStudy (anonymous):
no, r = (4/pi)^(1/3)
OpenStudy (anonymous):
ahh okay:)
so that's our r value right?
so now we need to find the h?
OpenStudy (anonymous):
you had the formula for h, find it, plug r in
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OpenStudy (anonymous):
so
8
-----
pi ((4/pi)^(1/3))^2 ?
not sure how to simplify that part though :/
OpenStudy (anonymous):
@sourwing ?
OpenStudy (anonymous):
8
--
pi (4/pi)^(2/3)
OpenStudy (anonymous):
oh! and that's as simplified as it gets?
OpenStudy (anonymous):
i think so
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