Question

Help Please!! Will fan and medal !!

Answer 1

long live @geerky42

Answer 2

Normal is perpendicular to tangent line so normal at f(3) is perpendicular to tangent line at f(3).

Given that normal is \(\dfrac{3\pi}{4}\) (aka 135 deg) away from x-axia, you just need to find the slope of line perpendicular to normal (90 deg away from 135 deg (aka 45 deg))

Answer 3

Make sense? @helpasap

Answer 4

Let say slope for line N is m. For line T, which is perpendicular to line N, the slope is -1/m.

Hope you can figure it out.