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@iambatman
|dw:1397194462236:dw|
Area A = Area of sector - Area of triangle OPR = 1/2 * r^2 * theta - 1/2 * r * r * sin(theta) = r^2/2( theta - sin(theta) ) Area B = 1/2 * QR * PQ = 1/2 * (r - rcos(theta)) * r * sin(theta) = r^2/2 * (1 - cos(theta)) * sin(theta) Area A / Area B = { r^2/2( theta - sin(theta) ) } / { r^2/2 * (1 - cos(theta)) * sin(theta) } = ( theta - sin(theta) ) / (1 - cos(theta)) * sin(theta) lim theta->0+ is 0/0. Apply L'H rule.
Alright, thank you very much for your help :)
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You are welcome.
I am getting 1/3. But have not double-checked it.
Yup, it was 1/3 :)
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