Question

Write the equation of the line that is parallel to the line y = -3x + 12 and passes through the point (-1, 6).

A. y= 1over3x + 7
B. y= -3x + 3
C. y= 1over3x + 3
D. y= -3x + 7

Please help!!!

Answer 1

please give me a medal its B. @meilendurcer

Answer 2

thank you!

Answer 3

Okay, first things first. In order for a line to be parallel to one another, they must both have the SAME SLOPE. In this case , y=-3x+12, the slope is 3.
So to find the equation of the other line whih passes through the points (-1, 6 ), substitue these into this , y=mx+c. ( Remember the equation for any straight -line graphs are in the form of y=mx+c.)
Because ur line has to passthrough the points (-1, 6 ) you have to substitute these points in:
so now it becomes 6= -3(-1)+ c ... -3 is your slope, 6 is your y, and -1 is your x. Then just solve it. You'll get c=3. Now you know what all your variables are, aand can write your equation for the seond line now. Y=-3x+3. I just plugged everything in y=mx+c form . Remember, m is the slope and c is the y-intercept. I hope this helped and I didn't just confuse you.