Question

please help i will give medals
find the axis of symmetry and the coordinates of the vertex of the graph of the function
y = -3x^2 + 12x + 1

Answer 1

@hoblos could you help??

Answer 2

for a parabola with equation y = ax^2+bx + c

the axis of symmetry is

x = -b/2a

can you get the axis now ?

Answer 3

im not sure

Answer 4

what are a,b and c in y = -3x^2 + 12x + 1
if you compare it to y = ax^2 + bx + c

Answer 5

a = -3x^2 b = 12x c = 1

Answer 6

im not sure how to put it together

Answer 7

a,b and c are the coefficients

i'll give you one , a= -3

Answer 8

b= 12??

Answer 9

like that

Answer 10

correct
and c ?

Answer 11

c=1

Answer 12

correctt

so -b/2a = ?

Answer 13

-3/2 = -1.5?

Answer 14

where did you get the 3 and 2 from ?

Answer 15

b = -3

Answer 16

i don't know

Answer 17

b=12 , and a=-3

so -b/2a = -12/2(-3) = ?

Answer 18

\[-\frac{ 12 }{ 2 \times -3 }\]

Answer 19

is that the answer?

Answer 20

you have to simplify it first

Answer 21

-12/-6?

Answer 22

correct
then ?

Answer 23

the answer is 2

Answer 24

correct, so the axis of symmetry is x=2

now for the vertex
the vertex is the intersection between the axis of symmetry and the parabola

thus the abscissa of the vertex is x=2

replace x=2 in the equation
what would be y ?

Answer 25

y = 13??

Answer 26

i want a medal

Answer 27

no