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help please: write the following as a single log using logarithmic properties 6log5u + 4log5v
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would the correct answer be 24log(u)(v)
where did you get the five from on the u?
\(6\log_5(u)+4\log_5(v)=\log_5(u^6)+\log_5(v^4)=\log_5(u^6v^4)\)
can you please explain one more problem to me please
\[2\log_{b}x+1/2\log_{b}y+\log_{b}z \]
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alogb=logb^a here the base is e this is a logarithm property
log a+log b = log(ab)
so how would you do this equation \[2\log_{b}x+1/2\log_{b}y+\log_{b}z \]
would it be like \[\log_{b}(x^6y^\frac{ 1 }{ 2 } z)\]
@aayushi.somani
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how u got x^6
sorry x^2
and how u got y^1/2
from the 1/2 thats in fron of log by the y
good and how u got z
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@numnum
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