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Mathematics 14 Online
OpenStudy (anonymous):

.

OpenStudy (kc_kennylau):

\[\Large\begin{array}{r|r}n&a_n\\\hline1&3\\\hline2&-6\\\hline3&12\end{array}\]

OpenStudy (kc_kennylau):

Find the common ratio first.

OpenStudy (kc_kennylau):

Common ratio = a2/a1 = a3/a2 = a4/a3 = ...

OpenStudy (anonymous):

-2 is the common ratio?

OpenStudy (kc_kennylau):

Yep

OpenStudy (kc_kennylau):

The explicit formula of a geometric sequence with first term \(a\) and common ratio \(r\) is: \[\Large a_n=ar^{n-1}\]

OpenStudy (kc_kennylau):

\(a\) is not 1, and please treat \(a_n\) as one entity (sorry for being confusing about a_n)

OpenStudy (kc_kennylau):

Yep :)

OpenStudy (kc_kennylau):

Again, please treat \(a_n\) as one entity and leave it there (I apologize again for confusing you)

OpenStudy (kc_kennylau):

Because \(a_n\) means the \(n\)th term.

OpenStudy (kc_kennylau):

Yes this is right

OpenStudy (kc_kennylau):

Yep :)

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