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\[\Large\begin{array}{r|r}n&a_n\\\hline1&3\\\hline2&-6\\\hline3&12\end{array}\]
Find the common ratio first.
Common ratio = a2/a1 = a3/a2 = a4/a3 = ...
-2 is the common ratio?
Yep
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The explicit formula of a geometric sequence with first term \(a\) and common ratio \(r\) is: \[\Large a_n=ar^{n-1}\]
\(a\) is not 1, and please treat \(a_n\) as one entity (sorry for being confusing about a_n)
Yep :)
Again, please treat \(a_n\) as one entity and leave it there (I apologize again for confusing you)
Because \(a_n\) means the \(n\)th term.
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Yes this is right
Yep :)
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