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anti-derivative of ( 1/ (x sqrt(4x^2 -1)))dx with the concept of http://prntscr.com/39apa9 Could someone please help me with this? :3
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\[\large \int\limits_{}^{} \frac{ 1 }{ x \sqrt{4x^2-1} }\]
I was thinking u-sub u = 2x ?
What about u=4x^2-1 ?
we were on trig inverses topic
you don't need any substitution
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put the x under the sqrt
Then you still need substitution?
not really
\[\int\limits_{}^{}\frac{ 1 }{ 4\sqrt{x^4-\frac{ x^2 }{ 4 }} }\]
anyways... I did u = 2x then du= 2dx so multiply top and bottom by 2 and got arcsec2x but textbook says 2arcsec2x that is my problem
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How did you get arcsec2x?
Do you know hyperbolics?
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