Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7
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OpenStudy (anonymous):
Is it: y = 1/28 x^2 ?
random231 (random231):
nah!
OpenStudy (anonymous):
No? Oh. -28y=x^2? @random231
random231 (random231):
no you got the axis wrong.
random231 (random231):
it shud be y^2=28x
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OpenStudy (anonymous):
That's not an option though. These are the options:
a. y 1/28 = x^2
b. x 1/28 = y^2
c. -28y = x^2
OpenStudy (anonymous):
@random231
OpenStudy (cwrw238):
standard form can be written
y^2 = 4 a x
where the focus is at ( a,0)
that would make it y" = 28x
but i'd have to check that out
OpenStudy (anonymous):
But how am I supposed to answer the question?
OpenStudy (cwrw238):
if the directrix is x = -7 and focus is at (7,0) that means the parabola opens to the right
and has the general equation
y^2 = 4 a x
where (a,0) is the focus
here a = 7
so the rquired equation is
y^2 = 4*7x
ie y^2 = 28x
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