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Mathematics 17 Online
OpenStudy (anonymous):

a. Calculate the scalar projection of (5,3) onto (7,-2). b. Interpret this projection graphically.

OpenStudy (anonymous):

the equation of a projection a on b is ((a.b)/(b.b))b Where a and b are vectors.

OpenStudy (anonymous):

b.b is also equal to Norm[b] squared

OpenStudy (ipwnbunnies):

I'm wrong, that is. I must be thinking about another projection, hmm.

OpenStudy (anonymous):

tell me if this is right? \[=(5\times7-3\times2)/\sqrt{53}\]

OpenStudy (anonymous):

yea thats teh scalar now multiply by the vector onto which you are projecting. in this case (7,-2)

OpenStudy (anonymous):

ok so my answer was for a correct?

OpenStudy (anonymous):

wait i meant -2

OpenStudy (anonymous):

not exactly, you found the scalar that you need to multiply with the vector itself to create the projection.

OpenStudy (anonymous):

also you accounted for the negative when you subtracted :P so you actually mean 2.

OpenStudy (anonymous):

http://upload.wikimedia.org/wikipedia/commons/thumb/3/3e/Dot_Product.svg/300px-Dot_Product.svg.png This is exactly what you are doing, just change the vectors to your own.

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