a. Calculate the scalar projection of (5,3) onto (7,-2). b. Interpret this projection graphically.
the equation of a projection a on b is ((a.b)/(b.b))b Where a and b are vectors.
b.b is also equal to Norm[b] squared
I'm wrong, that is. I must be thinking about another projection, hmm.
tell me if this is right? \[=(5\times7-3\times2)/\sqrt{53}\]
yea thats teh scalar now multiply by the vector onto which you are projecting. in this case (7,-2)
ok so my answer was for a correct?
wait i meant -2
not exactly, you found the scalar that you need to multiply with the vector itself to create the projection.
also you accounted for the negative when you subtracted :P so you actually mean 2.
http://upload.wikimedia.org/wikipedia/commons/thumb/3/3e/Dot_Product.svg/300px-Dot_Product.svg.png This is exactly what you are doing, just change the vectors to your own.
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