Laplace solving system dx/dt = -x +y dy/dt = 2x x(0)=0 y(0)=1
pew, last question
Hm. Did you know how to go about starting this one?
I do, but am not sure what to do after getting x(s) and Y(s)
X(s)(s+1)=Y(s) 2x+1=sY(s)
I believe you are just looking at solving for each like it were a linear system of equations. The first equation could be substituted into the second to let you find X(s), then find Y(s) using the result of X(s)...
X(s)(s+1)=Y(s) 2X(s)+1=sY(s)
Y(s) = X(s) (s + 1) --> 2 X(s) + 1 = s Y(s) => 2 X(s) + 1 = s (X(s) (s + 1)) <-- this is a one variable system ignoring the s, so we can isolate the X(s).
that's it? heh, that's not too bad. hmmn I can't seem to remember how to easily get Y(s) after though
just plug it in? I suppose
Yeah, whatever you get from X(s), plug that back into either of the two equations to solve for Y(s). The first is easier in this case.
pew, that was easy. Thanks, outta get some sleep lol
Haha, yea. I should be going to bed also... :P Good job, and gnight!
thanks again for the help!
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