A rock thrown into a pond causes a circular ripple. if the radius of the ripple is increasing by 3ft/sec how fast is the area changing when the radius is 12 feet?
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OpenStudy (anonymous):
Area of a circle: \[
A = \pi r^2
\]Can you differentiate with respect to time?
OpenStudy (anonymous):
Consider that area and radius are functions of time: \[
A(t) = \pi [r(t)]^2
\]
OpenStudy (anonymous):
the derivative would be 2πrr'(t) ?
OpenStudy (anonymous):
Yes.
OpenStudy (anonymous):
\[
A'(t) = 2\pi r(t) r'(t)
\]
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OpenStudy (anonymous):
Can you finish it?
OpenStudy (anonymous):
is the last equation to solve it 6π(12)?
OpenStudy (anonymous):
Yeah, you can simplify it more, but that is correct.
OpenStudy (anonymous):
so the answer would be 226.08ft/sec
OpenStudy (anonymous):
Answer is \(72\pi\; \text{ft}^2/\text{s}\)
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OpenStudy (anonymous):
wio im lost from A′(t)=2πr(t)r′(t) what numbers go in there
OpenStudy (anonymous):
\(r'(t) = 3 \;\text{ft/s}\) and \(r(t) = 12\; \text{ft}\)