A rock thrown into a pond causes a circular ripple. if the radius of the ripple is increasing by 3ft/sec how fast is the area changing when the radius is 12 feet?
Area of a circle: \[ A = \pi r^2 \]Can you differentiate with respect to time?
Consider that area and radius are functions of time: \[ A(t) = \pi [r(t)]^2 \]
the derivative would be 2πrr'(t) ?
Yes.
\[ A'(t) = 2\pi r(t) r'(t) \]
Can you finish it?
is the last equation to solve it 6π(12)?
Yeah, you can simplify it more, but that is correct.
so the answer would be 226.08ft/sec
Answer is \(72\pi\; \text{ft}^2/\text{s}\)
wio im lost from A′(t)=2πr(t)r′(t) what numbers go in there
\(r'(t) = 3 \;\text{ft/s}\) and \(r(t) = 12\; \text{ft}\)
okay so it would be 2π(12)(3)
Yes.
how did u get 72 for the answer
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