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Mathematics 14 Online
OpenStudy (anonymous):

Solve: -3 + |2x + 7| > 6

OpenStudy (anonymous):

A. x < 1 B. x < -8 and x > 1 C. x > -8 D. x > 1 or x < -8

OpenStudy (anonymous):

\[/2x+7/>9 -9>2x+7>9 -16>2x >2 -8>x >1

OpenStudy (anonymous):

then B is correct

OpenStudy (anonymous):

Thanks, can you help me with a couple more questions? If you don't mind of course.

OpenStudy (anonymous):

welcome yes , why not

OpenStudy (anonymous):

u guys form a great couple

OpenStudy (anonymous):

<3

OpenStudy (anonymous):

Is 8 a solution of x < -1 or x > 7? Please explain this to me as I literally don't know how to solve it.

zepdrix (zepdrix):

It might make more sense to you if they had worded it like this: Is `x=8` a solution of x < -1 or x > 7 ? Plug 8 in for x and see if both inequalities hold true.

zepdrix (zepdrix):

Woops, we have an `or`, so I guess you want to see if `either` holds true.

mathslover (mathslover):

\(\bf \bullet {\LaTeX \space \text{Tip :} }\\ \) ( @sarina89 ) `\[ Write your equation \]` - Don't forget to put "\]" at the end of equation too.

OpenStudy (anonymous):

So 8 > 7 holds true right? @zepdrix

OpenStudy (anonymous):

yes, indeed 8 > 7, your kindergarden teacher was right

OpenStudy (anonymous):

|dw:1397500612306:dw|

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