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Chemistry 13 Online
OpenStudy (anonymous):

How to prepare 165 ml of a 0.0268 M solution of benzoic acid in chloroform?

OpenStudy (anonymous):

Amount = M X M.wt X Vol / 1000 M=0.0268 M.wt=122 Vol=165 calculate the amount of benzoic acid dissolve in chloroform and make up the volume of chloroform upto 165 mL

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