NEED HELP ASAP I WILL FAN AND GIVE A MEDAL TO ANYONE WHO HELPS>
Would you please start off by posting the question you want to discuss, and ditch the "fan and medal" part of your post? It'd save time.
1. The distance traveled by an object can be modeled by the equation d = ut + 0.5at2 where d = distance, u = initial velocity, t = time, and a = acceleration. Solve this formula for a. Show all steps in your work. d = ut + 0.5at2 d = ut + 0.5at^2 d - ut = 0.5at^2 A=2d-ut/t^2 . is this right?
@mathmale
:)
Am i right
2(d-ut)/t^2= a
yes ! u are .
i have 4 more that i did on my own, can you check them?
sure !
post them right away here !
2. The distance traveled by a falling object is given by the formula d = 0.5gt2 where d = distance, g = the force of gravity, and t = time. Solve this equation for g, and use your formula to determine the force of gravity if a baseball takes 10 seconds to hit the ground after being dropped from a height of 490 feet. Show all steps in your work. d=0.5gt2 2dt2=g g=2(490)102=9.8
2d/t^2
and not 2dt^2
thank you
so my whole thing should be just 2d/t^2
:)
yes
Two boys want to use a seesaw and they need to move the seesaw so that their weights will balance out. The formula is given by w1 • d1 = w2 • d2 where w1 = weight of the first boy, d1 = distance of the first boy from the fulcrum, w2 = weight of the second boy, and d2 = distance of the second boy from the fulcrum. Rewrite the formula to solve for d2. Show all steps in your work .w1*d1=w2*d2 w2*d2/w2 = (w1*d1)/w2 d2 = w1*d1/w2
@CGGURUMANJUNATH
Marcie wants to enclose her yard with a fence. Her yard is in the shape of a triangle attached to a rectangle.The area of this figure can be found by the formula A = (wh) + 0.5(bh). If Marcie wants the total area to be larger than a specified value, she can use the formula A > (wh)+ 0.5(bh). Rewrite this formula to solve for b. Show all steps in your work.A - (wh) > 0.5(bh) A - (wh) / 0.5h > 0.5(bh) / 0.5h A - (wh) / 0.5h > b or b < A -(wh) / 0.5h a−wh÷0.5h=b
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