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Chemistry 20 Online
OpenStudy (anonymous):

HELP? :D An alpha particle (mass = 6.6 ✕ 10-24 g) emitted by radium travels at 3.2 ✕ 107 0.1 ✕ 107 mi/h. What is its de Broglie wavelength (in meters)?

OpenStudy (anonymous):

@SarahEZZMcK

OpenStudy (anonymous):

de Broglie's equation is λ = h / p, where λ is the wavelength, p is the momentum of the particle (mass times velocity), and h is Planck's constant. The plus minus thing is an uncertainty - that's how precise the measurement is. I don't know whether the problem requires that you calculate an uncertainty for your answer, but if so, you might try calculating the wavelength for 3.9 x 10^7 mph and seeing what the difference is. Yes Im a 14 year old geek but proud hope it helps

OpenStudy (anonymous):

why would i do 3.9 when my problem is 3.2? could you show me the steps so I can follow?

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