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OpenStudy (anonymous):
2x squared - 5x =3 solve using the quadratic formula please
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OpenStudy (anonymous):
@AccessDenied @Jadeishere @whpalmer4
OpenStudy (jadeishere):
so a = 2 b = -5 and c = -3
hero (hero):
\(2x^2 - 5x = 3\)
\(2x^2 - 5x - 3 = 0\)
2 = a
-5 = b
-3 = c
Plug those values into the quadratic formula:
\(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
OpenStudy (anonymous):
i don't know how to do the quadratic formula
OpenStudy (anonymous):
@Hero
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OpenStudy (anonymous):
\[2x ^{2}\]
hero (hero):
\[x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(2)(-3)}}{2(2)}\]
OpenStudy (anonymous):
what you do from there?
hero (hero):
Simplify it
OpenStudy (jadeishere):
so 2 = a, -5 = b and - 3 = c
so -(-5) = 5
(-5)^2 - 4(2)(-3) = 25 + 24 = 49
so x = 5 +- the square root 0f 49 all over 2 times 2
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OpenStudy (jadeishere):
\[x = \frac{ 5 \pm \sqrt {49} }{ 4} \]
OpenStudy (jadeishere):
the square root of 49 is 7
so x = 5 plus or minus 7 all over 4
x = 3 or x = -1/2
OpenStudy (anonymous):
thank you a million again
OpenStudy (jadeishere):
@Hero helped too
OpenStudy (anonymous):
true
THANKS HERO YOUR MY HERO @Hero
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