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Steve has these score on the exams for this semester: 89, 92, and 87. How much will have to make on the fourth exam to have a final average of an A (a 92% or better)?
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solve for x \[\frac{ 89+92+87+x }{ 400 } = .92\]
\[\frac{ 89+92+87+x }{ 4 }=92\] is how most would set that up, i think
^_^
So its %100?
not quite.. first we need to isolate the 'x' term, so clear fractions would be the first step, so times both sides by the denomenator
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