im stuck.
i need to solve for x, and i need an exact value, which means ill probably have a fraction of some kind
Have you considered that \(8^{2}+(5+x)^{2}=(Giant\;Hypotenuse)^{2}\)? There might be some Law if Sines in your future.
89+10x=x^2
=c^2
Try not to reuse variables in a single problem. This is the Pythagorean Theorem, \(Fred^{2} + Bob^{2} = Ralph^{2}\). There is nothing sacred about a, b, and c. It should lead you to the conclusion that \(x = \sqrt{H^{2}-64} - 5\), where H is the measure of the outer hypotenuse. Label the two acute angles and apply the Law of Sines liberally. See where it leads you.
i got sin b =\[(\sqrt{H ^{2}-8^2})\sin22/8^2+(5+x)^2\]
is that what you were getting at?
which equals H-8 on top right?
Or, the Law of Cosines might be helpful: \(H^{2} = 9.434^{2} + x^{2} - 2x\cdot 9.434\cdot\cos(122*deg)\) Pull out ALL the information available too you and find enough pieces!
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