If trapezoid ABCD was reflected over the y-axis, reflected over the x-axis,and rotated 180°, where would point A' lie?

(1,-1)

(-4,1)

(1,1)

(-4,-1)

Question

If trapezoid ABCD was reflected over the y-axis, reflected over the x-axis,and rotated 180°, where would point A' lie?

(1,-1)

(-4,1)

(1,1)

(-4,-1)

anonymous · Answer

attachment

jack1 · Answer

current location of A = (-4,1)
If trapezoid ABCD was reflected over the y-axis, 
location of A = (-4,-1)
reflected over the x-axis,
location of A = (4,-1)

jack1 · Answer

now...
and rotated 180°, where would point A' lie?
thats the weird one...

anonymous · Answer

You have to do all three. You have to reflect it twice and then rotate it.

jack1 · Answer

kk, so from the drawing u posted, if u rotated that 180... a would b at... ummm (0,2)... yeah?

jack1 · Answer

os it should be a 0, -2 then after reflexting twice... i think...?

anonymous · Answer

The answer is (-4, 1) because if you reflect it over the y-axis, point A should come out to (4, 1). Then when you reflect it over the x-axis, it becomes (4, -1). After it's been rotated 180 degrees it'll come out to (-4, 1) because when anything is rotated by 180 degrees, (x, y) becomes (-x, -y). Thanks for helping me but I figured it out! (:

jack1 · Answer

oh, ok, so the whole graph is rotated around the origin (0,0)
sorry, my bad, i thought only the shape was rotated  :-/

anonymous · Answer

No, it's alright. Thanks so much for trying(: