What is the solution of 3 lx + 5l <6? A. x ≤ -3 and x ≥ -7 B. No solution C. x ≥ -3 and x ≤ -7 D. x < -3 or x > -7
3 |x + 5| < 6 divide by 3 |x + 5| < 6/3 | x + 5 | < 2 (x + 5) < 2 -- subtract 5 from both sides x < 2 - 5 x < -3 -(x + 5) < 2 -x - 5 < 2 -- add 5 to both sides -x < 2 + 5 -x < 7 -- multiply by -1 to make x positive, and change inequality sign x > -7 Answer D
Thanks for the help, it was wrong tho.
@texaschic101
what ? It was wrong .....how ?
@ganeshie8 ....can you look at this please
this is absolutely right ! :) http://www.wolframalpha.com/input/?i=3*%7Cx+%2B+5%7C+%3C6
unless your question itself has some formatting error when u copy pasted from u homework page @Awesome_Naya
well when i sumbited it, i got a zero for that question
no, its the right question
doesnt matter, D is the right answer for this question !
maybe, take a snapshot of the original question and attach...
idk how, i'm on a computer
I thought I was going crazy there for a minute...thanks ganeshie :)
np :) wolfram is there for everything lol :P
is there supposed to be an equal sign in the problem ? That would make a difference
if there is an equal sign in the problem, then the answer would be A
no, its suposed to be less than & eaqual to, but i couldnt find that
lol, there settles the suspense ;)
so the problem is less then or equal to 6 ?? If so, then the answer is A. I can't make the equal sign with the inequality sign either, so I would put : 3 |x + 5| <= 6 that equal sign can make the difference between getting it right and getting it wrong
\(\large 3|x + 5| \le 6 \)
oh, so whats the difference ?
how'd you do that @ganeshie8
\(\large 3|x + 5| \le 6 \) is different from \(\large 3|x + 5| \lt 6 \)
showing off ganeshie...lol....I can't make that sign
hahah yes :)
Naya..if there is an equal sign in the problem, there will be an equal sign in the answer
\( \large 3|x + 5| \le 6 \(
try this again now
\( \large 3|x + 5| \lt 6 \)
copy paste below thing exactly in ur next reply : ``` \( \large 3|x + 5| \le 6 \) ```
try again now :)
\( \large 3|x + 5| \le 6 \)
Bingo :) you got it
i dont see the difference
the equal sign makes a difference. If there is an equal sign in the problem, there will be an equal sign in the answer. If there is no equal sign in the problem, then there will be no equal sign in the answer Understand ?
yeah, i have to go now
c ya :) thanks again ganeshie
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