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can someone look at this problem and tell me how they found the 45 please P(X=2)=(10 2) (0.25)^2 (0.75)^8 45 (0.25)^2 (0.75)^8 =.2816
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@satellite73
If 10 employed women are selected at random, what is the probability that exactly 2 have been married? n=10, p=0.25
\(\large \binom{10}{2} = ^{10}C_2 = \dfrac{10!}{2!(10-2)!}\)
its the number of ways of choosing 2 objects from a set of 10 objects.
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The formula is : \(\large \binom{n}{r} = ^{n}C_r = \dfrac{n!}{r!(n-r)!}\)
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