A 1385 kg cannon containing a 58.5 kg cannon ball is on wheels. The cannon fires the cannon ball, giving it a velocity of 49.8 m/s north. What is the initial velocity of the cannon the instant after it fires the cannon ball?
Initially, the total linear momentum is zero. The final total linear momentum will also be zero. I have arbitrarily assigned a positive direction for north for the final velocity of the cannon ball. When you solve for the final velocity of the cannon you will get a negative number, indicating that it moves in the opposite direction. This makes sense because the cannon recoils.\[\color{green}{\begin{align*} m_1\vec{v_1}^{'}+ m_2 \vec{v_2}^{'} &= 0 \\ (1\,385~\text{kg})(\vec{v_1}^{'}) + (58.5~\text{kg})(+49.8~\text{m/s}) &= 0\end{align*} } \]
yes i'm right xD thanks!
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