Question

simplify the radical expression. 3 sqrt 64x^12
a.4x^3
b.4x^4
c. 8x^3
d.8x^4

Answer 1

i'm not getting any of the options provided, ..

Answer 2

ok I mustve stated it wrong, like the 3 is the small 3 up on the edge of the sqrt sign

Answer 3

oh ok
\[\sqrt[3]{64x^{12}}=\sqrt[3]{64}\sqrt[3]{x^{12}}\\
%\qquad\qquad=3\sqrt{64}(x^{12})^{1/2}\\
%\qquad\qquad=3\sqrt{64}x^{12/2}\\
%\qquad\qquad=\\
%\qquad\qquad=\] like this?

Answer 4

\[\sqrt[3]{64x^{12}}=\sqrt[3]{64}\sqrt[3]{x^{12}}\\
\qquad\qquad=\sqrt[3]{64}(x^{12})^{1/3}\\
\qquad\qquad=\sqrt[3]{64}x^{12/3}\\
\qquad\qquad=\\
\qquad\qquad=\]

Answer 5

yeah you got it!

Answer 6

do you know how to simplify the cube root of 64?

Answer 7

would it be 4... cubed?

Answer 8

yeah 64 is the cube of 4 , so 4 is the cube root of 64

Answer 9

\[%\sqrt[3]{64x^{12}}=\sqrt[3]{64}\sqrt[3]{x^{12}}\\
%\qquad\qquad=\sqrt[3]{64}(x^{12})^{1/3}\\
\qquad\qquad=\sqrt[3]{4^3}x^{12/3}\\
\qquad\qquad=4x^{12/3}\\
\qquad\qquad=\]

Answer 10

so it would be 4x^4

Answer 11

yep,

Answer 12

cool, thank you!