Question

Lab Report:

empty crucible (+cover)-34.129
crucible (+cover) and hydrated salt- 36.082 g
crucible (+cover) and hydrate - 1st heat-35.382 g
crucible (+cover)and hydrate - 2nd heat- 35.381 g

Answer 1

1.determine the mass of the hydrated salt
2.determine the mass of the mass of the anhydrous salt
3.determine the number of moles of anhydrous salt
4. determine the mass of the water lost
5. determine the number of moles of the water lost
6. calculate the ratio of anhydrous salt : water lost
7. the above calculations give the value x in CuSO4 . xH2O write the correct formula for the hydrate
8. What is the IUPAC name given to this hydrate
9. What happened to the color of the product when you added water? what does this indicate?

Answer 2

I'm not sure what anhydrous means...but for the first question, subtract the first value you have from the second value.

Answer 3

anhydrous is when the hydrate loses the water. so then its just a salt

Answer 4

Oh okay, thanks! What does the 1st and 2nd heat mean?

Answer 5

it means the first time i heated it to get rid of the water. then the second time i heated it and got rid of all the water

Answer 6

So the 2nd heat is when it's just regular old salt without any water?

Answer 7

yup

Answer 8

the second heat got rid of all the water in the hydrate so then it turned anhydrous

Answer 9

Gotcha. For the second one, subtract the first value from the fourth.

Answer 10

If that makes sense. Subtract the first number (the crucible) from the fourth (2nd heat).

Answer 11

got it

Answer 12

Once you have the mass of the salt, you just convert that into moles. I'm sure you know how to do that.

Answer 13

yup

Answer 14

the real question is #6

Answer 15

im not sure what the number of the h20 is

Answer 16

Try to figure out 4 and 5. Those values will help with number 6.

Answer 17

yeah i did it im pretty sure its CuSO4 . 16 H2O but i could be wrong

Answer 18

Hmm..

Answer 19

oh well gn