factor completely 2x^3 + 18xy - 10x^2y - 90y please show me the steps. i am so confused!
@bahrom7893's can you help me?
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@sammixboo thanks so much! Do you think you can help me?
Yes! Just hold on ;)
okay thanks @sammixboo
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thanks so much!! @bahrom7893 ur a life saver
its okay. thanks for even helping! @bahrom7893
i don't think this sucker factors
@satellite73 thats what i thought but my teacher says it does. im home school and im so stuck!
besides the obvious factoring out a 2
I think it is supposed to be \[2 x^3 + 18 x y - 10 x^2 - 90 y\] \[(2x^3+18xy) +(-10x^2-90y)\]\[2x(x^2+9y) + (-10)(x^2+9y)\]\[(2x-10)(x^2+9y)\]\[2(x-5)(x^2+9y)\]
that looks more correct @whpalmer4 thanks so much!!!
I "factored" the other one a couple of times and kept scratching my head when I multiplied it out to check my work :-) Then the little light bulb glowed ever so faintly :-)
one last thing.. @whpalmer4 if the two middle terms were switched so that the expression became 2x^3 - 10x^2y + 18xy - 90 , would the answer still be the same?
I think you still have a spurious \(y\) in there...or in the wrong spot. The order of the terms makes no difference in the factoring.
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