Identify whether the series summation of 15 open parentheses 4 close parentheses to the I minus 1 power from 1 to infinity is a convergent or divergent geometric series and find the sum, if possible.

This is a convergent geometric series. The sum is –5.

This is a divergent geometric series. The sum is –5.

This is a convergent geometric series. The sum cannot be found.

This is a divergent geometric series. The sum cannot be found.

Question

Identify whether the series summation of 15 open parentheses 4 close parentheses to the I minus 1 power from 1 to infinity is a convergent or divergent geometric series and find the sum, if possible. 

 This is a convergent geometric series. The sum is –5. 

 This is a divergent geometric series. The sum is –5. 

 This is a convergent geometric series. The sum cannot be found. 

 This is a divergent geometric series. The sum cannot be found.

gavin39 · Answer

I believe its C

anonymous · Answer

still trying to read it
an equation editor might help

anonymous · Answer

be that as it may, if it is four to some power, it is geometric, but since $4\geq 1$ it is not summable

gavin39 · Answer

for some reason not letting me put it in

kirbykirby · Answer

Do you mean something like this: $$\sum_{i=1}^{\infty}15(4)^{i-1}$$?

gavin39 · Answer

yes!

kirbykirby · Answer

@satellite73 is right though, it's a geometric series with $|r|=4\ge 1$ which won't converge!

anonymous · Answer

so do you know what the right answer was? i hate this kinda math its horrible!

kirbykirby · Answer

If it's divergent, then you can't find its sum

anonymous · Answer

Thank you sooo much!!!