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A quadrilateral has vertices (-2,5), (-1,6), (3, 2), and (6, 1). If you translate it 3 units up and 7 units left, what are the coordinates of the vertices of its image?
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Do I add 3 and subtract 7 to each x and y value?
@jim_thompson5910 is that the right approach?
yes, but are you adding 3 to x? or y?
Add 3 to x and subtract 7 from y.
it says "translate it 3 units up"
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So I'd add 3 to y and subtract 7 from x?
correct
(x,y) ---> (x-7, y+3) is the rule you use
Thanks :)
you're welcome
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