Simplify the radical expression.
\[2\sqrt{6}+3\sqrt{96}\]
@nikato @AccessDenied
To simplify a radical expression like this, we need to get the same \( \sqrt{6} \) in each term. Then we can add these two: \(a \sqrt{6} + b \sqrt{6} = (a + b) \sqrt{6} \). So I'd factor out a \( \sqrt{6} \) from the \( \sqrt{96} \). If the remaining factor is a perfect square, we can simplify it to a coefficient. Does that make sense?
In this situation it is good to remember your rules for radicals. \( \sqrt{a * b} = \sqrt{a} \sqrt{b} \) \( \sqrt{96} = \sqrt{6 \times \color{red}{\dfrac{96}{6}}} = \sqrt{6} \sqrt{\color{red}{\dfrac{96}{6}}} \) Writing the 96/6 in red because you should be able to simplify that part.
Okay. I get it now. Thank you!
Glad to help! :)
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