Mathematics
14 Online
OpenStudy (anonymous):
Multiply and express the product in simplest form.
15x^2-y times 4y^2/xy
A.60x^2/y^2
B.60x
C.15xy^3/4y^2
D.15x^3y/4y^3
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OpenStudy (anonymous):
@davidmack
OpenStudy (anonymous):
help me please!
OpenStudy (anonymous):
@ganeshie8
ganeshie8 (ganeshie8):
\(\large (15x^2-y)\times \dfrac{ 4y^2}{xy}\)
ganeshie8 (ganeshie8):
like that ?
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ganeshie8 (ganeshie8):
could u take snapshot and post if psble... ? :)
OpenStudy (anonymous):
ganeshie8 (ganeshie8):
ty :)
ganeshie8 (ganeshie8):
\(\large \dfrac{ 15x^2}{y} \times \dfrac{ 4y^2}{xy}\)
ganeshie8 (ganeshie8):
first multiply the constants : 15*4
wat do u get ?
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OpenStudy (anonymous):
60
ganeshie8 (ganeshie8):
\(\large \dfrac{ 15x^2}{y} \times \dfrac{ 4y^2}{xy}\)
\(\large \dfrac{ 60x^2}{y} \times \dfrac{ y^2}{xy}\)
ganeshie8 (ganeshie8):
yes :)
ganeshie8 (ganeshie8):
bottom you have two y's, and top you have y^2.
can we cancel them both ?
OpenStudy (anonymous):
okay..umm...yes?
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ganeshie8 (ganeshie8):
\(\large \dfrac{ 15x^2}{y} \times \dfrac{ 4y^2}{xy}\)
\(\large \dfrac{ 60x^2}{y} \times \dfrac{ y^2}{xy}\)
\(\large 60x^2 \times \dfrac{1 }{x}\)
ganeshie8 (ganeshie8):
lastly cancel one x also
ganeshie8 (ganeshie8):
\(\large 60x^2 \times \dfrac{1 }{x}\)
\(\large 60x\)
ganeshie8 (ganeshie8):
see if that makes more or less sense.. .
OpenStudy (anonymous):
omg thank you soo much and yes it does! :)
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ganeshie8 (ganeshie8):
good to hear :) u wlc !