Question

What are the zeroes of f(x) = x2 - 2x - 3?

x = -3, 1

x = -3, -1

x = 3, 1

x = 3, -1

Answer 1

all you have to do is factor it.
\[x^{2} - 2x - 3\]
(x-3)(x+1)
x-3 = 0 x+1 = 0
x= 3 x= -1
so the zeros are 3,-1