Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).
@jigglypuff314 do you understand this?
a perpendicular line has a flipped opposite slope so first figure out what is the slope of the line given and then take the flipped opposite of it like if given slope = 3 then perpendicular slope = -1/3
So, how would I figure that? Solve for x? and get Y = x?
it's already in slope intercept form y = mx + b where m = slope :)
OH! Okay! XD Wow.
\[Y = 2x + 6\] \[Y = -\frac{ 1 }{ 2 } + 3\] \[Y = -\frac{ 1 }{ 2 } + 6\] \[Y = 2x + 3\]
I think A, but I'm confused. Functions are strange..
well, what did you get as the slope for y = 2x +2 ? :)
2x?
close :) It would be just 2 now, what would be the flipped opposite of 2?
-2
don't forget flipped so -1/2 :) now, can you make an equation out of slope = -1/2 and point (6, 3) ?
I was about to say that! and its C! :D
Correct! :)
Thank you so much!
You're Welcome ^_^
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