Question

Determine if the expression is a perfect square and if it is, factor it.

16a2 + 8a + 1

A.
not a perfect square

B.
(a + 4)(a – 4)

C.
(a – 4)(a – 4)

D.
(4a + 1)2

Answer 1

here is a hint to get you started ^_^

a perfect square must have:
- two terms that are squares
- and the remaining term must be 2*A*B

can you pick out the two terms in your problem that are squares?

Answer 2

B @DemolisionWolf

Answer 3

its either B or C

Answer 4

mm... not quite

I'll show ya!
16a2 + 8a + 1
=(4a)^2 + 8a + 1^2

now, see how 4a is like A and 1 is like B in this formating?
A^2 + 2AB + B^2

that above equals
= (A+B)^2

so, lets substitute our 'A' and 'B' in
if A = 4a and
B = 1, then we would get

(4a + 1)^2

Answer 5

Factor.

v2 – 36

A.
(v – 6)(v – 6)

B.
(v + 6)(v – 6)

C.
(v2 – 6)2

D.
(v – 6)2

Answer 6

v^2 – 36

36 is a square, it is 6^2

=v^2 - 6^2

next, use the difference of squares method to solve this one: it looks like this..
A^2 - B^2
=(A - B) (A + B)

Answer 7

what was the answer to the last one afterall?