Factor.
2x2 – x – 6
A.
(2x + 3)(x – 2)
B.
(2x – 3)(x – 2)
C.
(2x – 2)(x + 3)
D.
(2x – 3)(x + 2)
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OpenStudy (anonymous):
(2x+3)(x−2)
OpenStudy (jadeishere):
(2x - 3)(x + 2)
OpenStudy (jadeishere):
-3x + 2x = -x
3x - 2x = +x
OpenStudy (anonymous):
so A?
OpenStudy (anonymous):
yupperdoodles :)
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OpenStudy (anonymous):
Factor completely.
3x3 – 48x
A.
3x(x – 16)
B.
3x(x – 4)(x – 4)
C.
3(x + 4)(x – 4)
D.
3x(x – 4)(x + 4)
OpenStudy (anonymous):
@DemolisionWolf
OpenStudy (anonymous):
3x(x+4)(x−4)
OpenStudy (anonymous):
It's C :)
OpenStudy (anonymous):
3x3 – 48x
first, factor out all common factors from both terms,
we have an 'x' in both and... a 3
48 = 3 * 16
3x( x^2 - 16)
recognize that 16 is a square, its 4^2
re write the expression
(3x) (x^2 - 4^2)
looks like we have a 'difference of squres'
they look like this:
(A^2 - B^2)
= (A - B) (A + B)
can you rewrite our expressing using this method of 'differnce of squres'?