Question

(logx)^2
+
log(x^3)
+2
=0

solve for x

Answer 1

so you know we can rewrite log(x^3) as 3log(x)

so do you know how to solve u^2+3u=0?

Answer 2

oh ty let me solve now and get back to you

Answer 3

k

Answer 4

so

u(u+3)

u=logx

so when logx =0
and when log (x)+3 =0 ?

Answer 5

right

Answer 6

you are good so far

Answer 7

1 and 10^-3

Answer 8

I think you forgot the +2 part

Answer 9

yeah that is what i got

Answer 10

oh i didn't see the plus 2 part

Answer 11

@illuminator123 do you see what sour pointed out?

Answer 12

we are now looking at \[u^2+3u+2=0\]

Answer 13

yes

u+2 and U+1 are the 2 binomials

Answer 14

ok great and you said log(x)=u

so you have log(x)+2=0 or log(x)+1=0

Answer 15

10^-2

10^-1 =x

Answer 16

yep yep gj

Answer 17

thx