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if x varies jointly as y and z, and x=10 when y=4 and z=15, find x when y=8 and z=20
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do you have more points? because it could be many things from that setup x could be 13 y: 4->8 = +4 z: 15->20 +5 so x: 10->13 +3 just a guess
I'm afraid those are the only points i was given
So x varies jointly as y and z would be x=k(yz) Plugging in x=10, y=4, z=15 10=k(4)(15) Now solve for k
so k would = .16?
Not quite. k=1/6 10=60k. Divide 60 So k=1/6
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So you have x=1/6 (yz) And you have y=8 and z=20 And you're trying to solve x. So plug the numbers in x=1/6 (8)(20) So what's x?
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